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Madilynn Maxwell
Chemistry
6 December, 04:52
H2O2 (aq) = O2 (g) in acidic solution
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Lincoln Acevedo
6 December, 05:18
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(1) Assign oxidation states. In this case, the H is + 1, the O in peroxide is - 1 and in O2 is 0. Since you've only got something being oxidized here, you're only going to get an oxidation half-reaction.
(2) Write the half-reaction skeleton, with just the species being oxidized or reduced, and the electrons in the right place: H2 O2 (aq) → O2 (g) + 2 e -
Notice I put two electrons being released, because two oxygen atoms are being oxidized from - 1 to 0.
(3) Balance elements other than O and H. Already done.
(4) Balance oxygen by adding water to the appropriate side. Don't need to.
(5) Balance hydrogen by adding H+: H2 O2 (aq) →2 H + (aq) + O2 (g) + 2 e-
(6) If your reaction is in acid solution, you're done. If it's in basic solution, add OH - to both sides to cancel the H+: H2 O2 (aq) + 2 OH - (aq) →2 H2 O (l) + O2 (g) + 2 e-
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