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6 November, 22:46

A sample of NO2 in a 1550 mL metal cylinder at 70.26 kPa has its temperature changed from 480oC to - 237oC while its volume is simultaneously changed by a piston to 5114 mL. What is the final pressure in kPa?

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  1. 6 November, 22:53
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    1.02KPa

    Explanation:

    The following were obtained from the question:

    V1 = 1550mL

    P1 = 70.26kPa

    T1 = 480°C = 480 + 273 = 753K

    T2 = - 237°C = - 237 + 273 = 36K

    V2 = 5114mL

    P2 = ?

    The final pressure can obtain as follows:

    P1V1/T1 = P2V2/T2

    (70.26x1550) / 753 = (P2x5114) / 36

    Cross multiply to express in linear form as shown below:

    P2 x 5114 x 753 = 70.26 x 1550 x 36

    Divide both side by 5114 x 753

    P2 = (70.26x1550x36) / (5114x753)

    P2 = 1.02KPa

    Therefore, the final pressure is 1.02KPa
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