4Al + 3O2 = 2Al2O3

In this chemical reaction, how many grams of Al2O3 will be produced if 375 grams of Al react completely?

Answer: 708.3g of Al2O3 will be produced

Explanation:

4Al + 3O2 - > 2Al2O3

MM of Al2O3 = (27x2) + (3x16) = 54 + 48 = 102g/mol

Mass conc. Of Al2O3 = 2 x 102 = 204g

MM of Al = 27g/mol

Mass conc. Of Al = 4 x27 = 108g

From the equation,

108g of Al produced 204g of Al2O3.

Therefore,

375g of Al will produce Xg of Al2O3 i. e

Xg of Al2O3 = (204 x 375) / 108 = 708.3g.