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19 February, 12:12

How many moles of C12H22O11C12H22O11are needed to prepare 2.50 L of 0.300 M solution?

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  1. 19 February, 12:40
    0
    0.75 mol

    Explanation:

    concentration=mole/volume

    c*v=n

    volume=2.50l=2.50dm³

    0.300*2.50=0.75mol
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