How many grams of nitroglycerin are needed to produce 25.0 grams of CO2

Nitroglycerin decomposes according to the following equation

4 C3H5N309 - - - > 12 CO2 + 10 H20 + 6 N2 + O2

The moles of CO2 = 25 / 44 (molar mass of CO2) = 0.568 moles

the mole ratio of C3H5N3O9 to CO2 IS 4:12 from equation above

therefore the moles of C3H5N3O9 = (0.568 x 4) / 12 = 0.189 moles

mass of C3H5N3O9=moles x molar mass of C3N5N3O9

That is 0.189 mol x 227 g/mol = 42.903 grams