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11 April, 01:02

A marshmallow has an initial volume of 0.033 L at standard pressure (1.0 atm). If the marshmallow is placed in a vacuum chamber and the final volume is 0.439L, what is the pressure inside the chamber?

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  1. 11 April, 01:09
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    0.075 atm

    Explanation:

    P1V1 = P2V2

    1.0 atm * 0.033L = P2 * 0.439 L

    P2 = 1*0.033/0.439 = 0.075 atm
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