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24 December, 03:26

If 1.27 moles of bromine gas (Br2) react with excess phosphorus (P), how many moles of phosphorus tribromide (PBr3) will be produced?

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  1. 24 December, 03:48
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    0.85 mole of PBr3.

    Explanation:

    We'll begin by writing the balanced equation for the reaction. This is given below:

    3Br2 + 2P - > 2PBr3

    From the balanced equation above,

    3 moles of Br2 reacted to produce 2 moles of PBr3.

    Therefore, 1.27 moles of Br2 will react to produce = (1.27 x 2) / 3 = 0.85 mole of PBr3.

    Therefore, 0.85 mole of PBr3 is produced by the reaction.
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