How many moles of c6h14 contain 9.25 * 1024 molecules of c6h14?

Question

Kamren

Chemistry

1 October, 07:16

How many moles of c6h14 contain 9.25 * 1024 molecules of c6h14?

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Answers (1)

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Weston Juarez · Answer 1

According to Avagadros law 1 mole of a substance contains 6.02 * 10^23 particles.

Thus, 1 mole of C6H14 contains 6.02 * 10^ 23 molecules,

Therefore, 9.25 * 10^24 molecules will have;

(9.25 * 10^24) / (6.02 * 10^23)

= 15.365 moles.