Part a in an effusion experiment, it was determined that nitrogen gas, n2, effused at a rate 1.812 times faster than an unknown gas. what is the molar mass of the unknown gas? express your answer to four significant figures and include the appropriate units.

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Chemistry

19 September, 01:33

Part a in an effusion experiment, it was determined that nitrogen gas, n2, effused at a rate 1.812 times faster than an unknown gas. what is the molar mass of the unknown gas? express your answer to four significant figures and include the appropriate units.

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Roberto Garrison · Answer 1

Effusion rate, R, is inversely proportional to the square root of the molar mass, M:

R α 1 / √M

Let Ra be the effusion rate of a gas with molar mass Ma and Rb the efussion rate of a gas with molar mass Mb, then:

Ra / Rb = √ [Mb / Ma]

You know Ra / Rb = 1.82 and Ma = molar mass of N2 = 28.02 g/mol

=> Mb = [Ra / Rb]^2 * Ma = (1.82) ^2 * 28.02 g/mol = 92.81 g/mol

Answer: 92.81 g/mol