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27 September, 00:58

Which of the following systems (i. e., pair of metals) would you expect to exhibit complete solid solubility? Cr-V Mg-Zn Al-Zr

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  1. 27 September, 01:02
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    The system that will exhibit complete solid solubility is Cr-V

    Explanation:

    The following factors must be examined to check which of the systems that will exhibit complete solubility

    1. Crystal Structure (Same or Different)

    2. The difference of their atomic radius has to be less than ±15% and

    3. The difference in electronegativity

    Having highlighted these factors, we'll check for each of the pair of metals

    1.

    Cr - V

    Chromium and Vanadium

    Cr

    Electronegativity = 1.6

    Atomic Radius = 0.125

    Vanadium.

    Electronegativity = 1.6

    Atomic Radius = 0.132

    Difference in atomic radius = (0.125 - 0.132) / 0.125

    Difference = - 0.007/0.125

    Difference = - 0.056

    Difference = - 5.6%

    a. They have the same crystal structure

    b. They have the same electronegativity

    c. Difference in atomic radius is less than ±15%

    2.

    Mg - Zn

    Magnesium and Zinc

    Magnesium

    Electronegativity = 1.2

    Atomic Radius = 0.16

    Zinc

    Electronegativity = 1.6

    Atomic Radius = 0.133

    Difference in atomic radius = (0.16 - 0.133) / 0.16

    Difference = 0.027/0.16

    Difference = 0.16875

    Difference = 16.875%

    They have the different electronegativity

    The Difference in atomic radius is greater than ±15%

    3.

    Al - Zr

    Aluminum and Zirconium

    Aluminum

    Electronegativity = 1.5

    Atomic Radius = 0.143

    Zirconium

    Electronegativity = 1.4

    Atomic Radius = 0.148

    Difference in atomic radius = (0.143 - 0.148) / 0.143

    Difference = - 0.005/0.143

    Difference = - 0.034965

    Difference = - 3.4965%

    a. They have the same crystal structure

    b. They have the different electronegativity

    c. Difference in atomic radius is less than ±15%
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