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12 August, 14:58

Combustion analysis of an unknown compound provides the following dаta: 73.5 grams carbon (C), 4.20 grams hydrogen (H) and 72.3 grams chlorine (Cl). What is the percent composition of each element in this compound?

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  1. 12 August, 15:15
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    M (C) = 73.5 g

    m (H) = 4.20 g

    m (Cl) = 72.3 g

    mass of compound

    m=m (C) + m (H) + m (Cl)

    m=73.5+4.20+72.3=150 g

    w (H) = 100m (H) / m

    w (H) = 100*4.20/150=2.8%

    w (Cl) = 100m (Cl) / m

    w (Cl) = 100*72.3/150=48.2%

    w (C) = 100-w (H) - w (Cl)

    w (C) = 100-2.8-48.2=49.0%
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