How many moles of PCl5 can be produced from 22.0 g of P4 (and excess Cl2) ?

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Delgado

Chemistry

3 April, 10:41

How many moles of PCl5 can be produced from 22.0 g of P4 (and excess Cl2) ?

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Skyla Rose · Answer 1

The balanced chemical reaction is written as:

P4 + 10Cl2 = 4PCl5

To determine the moles of PCl5 produced, we use the initial amount of the limiting reactant which is P4 and the relation from the reaction. We do as follows:

22.0 g P4 (1 mol / 123.90 g) (4 mol PCl5 / 1 mol P4) = 0.7103 mol PCl5 produced