A 1.5 L container holds 0.50 grams of an unknown gas at a pressure of 0.44 atm and a temperature of 50. C. What is the molar mass of the unknown gas?

A.) 0.16g/mol

B.) 0.025 g/mol

C.) 2030 g/mol

D.) 20.1 g/mol

Question

Drake Stevens

Chemistry

30 September, 07:54

A 1.5 L container holds 0.50 grams of an unknown gas at a pressure of 0.44 atm and a temperature of 50. C. What is the molar mass of the unknown gas?

A.) 0.16g/mol

B.) 0.025 g/mol

C.) 2030 g/mol

D.) 20.1 g/mol

+5

Answers (1)

Know the Answer?

Damarion Ramos · Answer 1

To simplify the problem, we assume that the gas is ideal so we use the ideal gas equation for this which is expressed as PV=nRT. First, we calculate for the number of moles, n, of the system.

n = PV/RT

n = 0.44 (1.5) / 0.08205 (323.15)

n = 0.025 mol

Molar mass = 0.50 g / 0.025 mol

Molar mass = 20 g / mol

A 1.5 L container holds 0.50 grams of an unknown gas at a pressure of 0.44 atm and a temperature of 50. C. What is the molar mass of the unknown gas?A.) 0.16g/molB.) 0.025 g/molC.) 2030 g/molD.) 20.1 g/mol

A 1.5 L container holds 0.50 grams of an unknown gas at a pressure of 0.44 atm and a temperature of 50. C. What is the molar mass of the unknown gas?

A.) 0.16g/mol

B.) 0.025 g/mol

C.) 2030 g/mol

D.) 20.1 g/mol