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31 March, 13:07

A.) Thermal Decomposition of 2.765 g NaHCO3 yields 1.234g of a solid Na2CO3. Calculate the theoreticial yield and percent yield of Na2CO3.

B) Thermal decomposition of 2.968 g of a mixture containing NaHCO3 lost 0.453 g. Calculate the percentage of NaHCO3 in this unknown mixture

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  1. 31 March, 13:19
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    2NaHCO3 - > Na2CO3 + H2O + CO2

    2.765g NaHCO3/MM = moles NaHCO3

    moles NaHCO3 x (1 mole Na2CO3 / 2 moles NaHCO3) x MM Na2CO3 = theoretical yield of Na2CO3

    Percent yield is simply the actual yield/theoretical yield (x100 to put it into percentage).

    MM = Molar mass (grams of substance per mol)
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