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11 September, 06:39

If the dimensions of a cube-shaped cell with a volume of 1 pm were to

double, what would be the new surface area of the cell?

O A: 12 um

O B. 24 uma

O c. 6um

O D. 3 um

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Answers (1)
  1. 11 September, 06:50
    0
    B

    Explanation:

    Assuming the units are all supposed to be the same

    A cube shaped cell with a 1 um³ volume would have a dimensions of 1 x 1 x 1 (because volume = length x width x height and 1 x 1 x 1 = 1)

    If we double the dimensions, we have a cube with the dimensions 2 x 2 x 2.

    The surface area of each face of the cube is the length x width, so 2 x 2. This means the surface area of each face of the cube is 4 um².

    There are 6 faces of a cube, so the total surface area is 6 x 4 um² = 24 um².
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