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24 January, 22:27

A 50.0 - mL sample of 1.50*10-2 M Na2SO4 (aq) is added to 50.0 mL of 1.28*10-2 M Ca (NO3) 2 (aq). What percentage of the Ca2 + remains unprecipitated?

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  1. 24 January, 22:31
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    When we have Ksp CaSO4 = 9.1x10^-6 so by substitution in Ksp formula:

    Ksp CaSO4 = [Ca+2][SO4]

    1.9x10^-6 = [Ca+2][1.5x10^-2]

    ∴ [Ca+2] M in the solution = 1.27x10^-4

    when percent remaining = [Ca in solution]/[C original value] * 100

    = [ (1.27x10^-4 * (50ml+50ml) ]/[1.28x10^-2*50ml]*100

    ≈ 2%
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