Consider the balanced reaction bellow. How many moles of barium hydroxide, Ba (OH) 2, would be required to react with 117g hydrogen bromide, 2HBr+Ba (OH) 2=BaBr2+2H2

Question

Heisenberg

Chemistry

24 March, 13:50

Consider the balanced reaction bellow. How many moles of barium hydroxide, Ba (OH) 2, would be required to react with 117g hydrogen bromide, 2HBr+Ba (OH) 2=BaBr2+2H2

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Maryjane Joyce · Answer 1

Mol of HBr = mass/Mr = 117 / (1+80) = 1.444 From equation, 2 moles hydrogen bromide reacts with 1 mole of barium hydroxide ... So 1.444 moles of hydrogen bromide react with (1.444/2) = 0.722 moles of barium hydroxide.