A mixture of krypton and argon gas is expanded from a volume of 33.0L to a volume of 61.0L, while the pressure is held constant at 58.0atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

Question

Peyton Wong

Chemistry

13 March, 16:35

A mixture of krypton and argon gas is expanded from a volume of 33.0L to a volume of 61.0L, while the pressure is held constant at 58.0atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

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Answers (1)

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Albert Potter · Answer 1

W = + 1624J

Explanation:

V1 = 33.0L

V2 = 61.0L

P = 58 atm

Work = force * distance (∇x)

Work = F.∇x

But force = pressure * area

F = P. A

Work = P.∇x. A

Work = P∇v

Work = P (V₂ - V₁)

Work = 58 * (61 - 33)

Work = 58 * 28

Work = 1624J

The work done is + 1624J