The gas in an engine cylinder is compressed until it has a volume of 0.045 liter and an absolute pressure of 28 atmospheres. If the engine cylinder contains 0.020 mole of gas, what is its temperature? The temperature of the gas is how many K.

The temperature in K is 767.4 K

calculation

This is calculated using the ideal gas equation

that is PV = nRT

where;

P (pressure) = 28 atm

V (volume) = 0.045 L

n (number of moles) = 0.020 moles

R (gas constant) = 0.0821 L. atm/mol. K

T (temperature) = ? K/

make T the subject of the formula by diving both side of equation by nR

T = PV/nR

T = { (28 atm x 0.045 L) / (0.020 mol x 0.0821 L. atm/mol. K) } = 767.4 K

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