How many liters are in 2.5 moles of Chlorine gas?

Volume of the chlorine gas is 0,056 m³.

Explanation:

p * V = n * R * T

p = 101325 Pa

n = 2,5 moles

R = 8,31446 J K⁻¹ moles⁻¹

T = 273,15 K

(standard conditions)

V = (n * R * T) / p = (2,5 moles * 8,31446 J K⁻¹ moles⁻¹ * 273,15 K) / 101325 Pa

V = 0,056 m³