A solution contains 0.750 g of mg2 in enough water to make a 1875 ml solution. what is the milliequivalents of mg2 per liter (meq/l) for this solution

Question

Augustus Harding

Chemistry

24 March, 15:00

A solution contains 0.750 g of mg2 in enough water to make a 1875 ml solution. what is the milliequivalents of mg2 per liter (meq/l) for this solution

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Shayla · Answer 1

The answer is "32.9 meq/liter".

1875ml = 1875 / 1000 = 1.875ml

mass of magnesium = 24.305 g

0.750 g Mg² + x 1 mole Mg²⁺/24.305 g x 2 equivalents/mole

= 0.617 equivalents0.0617 eq x 1000 meq/eq = 61.7 meq37.4 meq/1.875 L = 32.9 meq/liter