Compute the concentration of HCl for all three trials using the formula molarity = mol / L. Trial 1 (20.61 mL HCl) : M Trial 2 (20.06 mL HCl) : M Trial 3 (19.67 mL HCl) : M

Question

Asher Pearson

Chemistry

5 March, 17:04

Compute the concentration of HCl for all three trials using the formula molarity = mol / L. Trial 1 (20.61 mL HCl) : M Trial 2 (20.06 mL HCl) : M Trial 3 (19.67 mL HCl) : M

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Answers (2)

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Alonso Johnson · Answer 1

Trial 1 (20.61 mL HCl):

⇒ 0.121 M

Trial 2 (20.06 mL HCl):

⇒ 0.125 M

Trial 3 (19.67 mL HCl):

⇒ 0.122 M

0.123 M.

Ruth Brandt · Answer 2

Trial 1 (20.61 mL HCl):

⇒ 0.121 M

Trial 2 (20.06 mL HCl):

⇒ 0.125 M

Trial 3 (19.67 mL HCl):

⇒ 0.122 M

the answer for the next question, Compute the average concentration (molarity) of HCl for all three trials, is 0.123 M.