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5 March, 17:04

Compute the concentration of HCl for all three trials using the formula molarity = mol / L. Trial 1 (20.61 mL HCl) : M Trial 2 (20.06 mL HCl) : M Trial 3 (19.67 mL HCl) : M

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  1. 5 March, 17:08
    0
    Trial 1 (20.61 mL HCl):

    ⇒ 0.121 M

    Trial 2 (20.06 mL HCl):

    ⇒ 0.125 M

    Trial 3 (19.67 mL HCl):

    ⇒ 0.122 M

    0.123 M.
  2. 5 March, 17:29
    0
    Trial 1 (20.61 mL HCl):

    ⇒ 0.121 M

    Trial 2 (20.06 mL HCl):

    ⇒ 0.125 M

    Trial 3 (19.67 mL HCl):

    ⇒ 0.122 M

    the answer for the next question, Compute the average concentration (molarity) of HCl for all three trials, is 0.123 M.
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