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8 December, 22:26

In a 1.0-liter container there are, at equilibrium, 0.10 mole h2, 0.20 mole n2, and 0.40 mole nh3. what is the value of kc for this reaction at this temperature

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  1. 8 December, 22:42
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    The reaction involved here would be written as:

    2N2 + 3H2 = 2NH3

    The equilibrium constant of a reaction is the ratio of the concentrations of the products and the reactants when in equilibrium. The expression for the equilibrium constant of this reaction would be as follows:

    Kc = [NH3]^2 / [N2]^2[H2]^3

    Kc = 0.40^2 / (0.20) ^2 (0.10) ^3

    Kc = 4000
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