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3 March, 01:34

What is the [oh-] in a solution with a poh of 11.25

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  1. 3 March, 01:38
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    The [Oh-] in the solution with a POh of 11.25 is 5.623 x 10^-12 M

    calculation

    POH = - log [ OH-]

    Therefore - log [oH-] = 11.25

    To calculate [oh-] concentration find the antilog of 11.35

    = 10^ - 11.25 = 5.623 x 10^-12 M
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