What is the osmotic pressure, in torr, of a 3.00% solution of NaCl in water when the temperature of the solution is 45 ºC? Enter your answer scientific notation.

213034 torr is the osmotic pressure.

Explanation:

osmotic pressure is calculated by the formula:

osmotic pressure = iCrT

where i = no. of solute

c = concentration in mol/litre

R = Universal Gas constant

T = temp

It is given that solution is 3% which is 3gms in 100 ml.

let us calculate the concentration in moles/litre

3gm/100ml*1000ml/1L*1mol NaCl/55.84g NaCl

= 5.372 gm/litre

Putting the values in the formula, Temp in Kelvin 318.5K

osmotic pressure = 2*5.372*0.083 * 318.5 Gas constant 0.083

= 284.023 bar or 213018 torr. c = 5.372 moles/L

i=2 for NaCl