Complete and balance the equation for the combustion of zns in excess oxygen? zns + ? o2→? zno + ? use no fractional coefficients. the number of moles and the formula of the product containing s are

The combstion of ZnS in excess oxygen gives ZnO and SO₂ as the products.

hence the equation should be;

ZnS (s) + O₂ (g) →ZnO (s) + SO₂ (g)

At the left hand side: At the right hand side:

number of Zn atoms = 1 number of Zn atoms = 1

number of S atoms = 1 number of S atoms = 1

number of O atoms = 2 number of O atoms = 3

Hence the balanced equation is;

2ZnS (s) + 3O₂ (g) →2ZnO (s) + 2SO₂ (g)