Determine the molarity of a solution made by dissolving 8.36 g of MgCl2 in water where the final volume of the solution is 500.0 mL.

Question

Alexis Levine

Chemistry

14 December, 19:22

Determine the molarity of a solution made by dissolving 8.36 g of MgCl2 in water where the final volume of the solution is 500.0 mL.

+5

Answers (1)

Know the Answer?

Nathanial Patrick · Answer 1

Answer is: the molarity of the solution is 0.176 M.

m (MgCl₂) = 8.36 g; mass of magnesium chloride.

M (MgCl₂) = 95.21 g/mol; molar mass of magnesium chloride.

n (MgCl₂) = m (MgCl₂) : M (MgCl₂).

n (MgCl₂) = 8.36 g : 95.21 g/mol.

n (MgCl₂) = 0.0878 mol; amount of magnesium chloride.

V = 500 mL : 1000 mL/L.

V = 0.5 L; volume of the solution.

c (MgCl₂) = n (MgCl₂) : V.

c (MgCl₂) = 0.0878 mol : 0.5 L.

c (MgCl₂) = 0.176 mol/L; the molarity of the solution.