Suppose on an average day air contains 6.5 mg of carbon monoxide per 1000 m 3 3 of air. How many milligrams of carbon monoxide are in a room measuring 10 ft x 10 ft x 10 ft? (1m = 3.28 ft). Do not use scientific notation.

Question

Clay Mcintyre

Chemistry

31 August, 22:56

Suppose on an average day air contains 6.5 mg of carbon monoxide per 1000 m 3 3 of air. How many milligrams of carbon monoxide are in a room measuring 10 ft x 10 ft x 10 ft? (1m = 3.28 ft). Do not use scientific notation.

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Sanaa Reeves · Answer 1

Answer is: there is 0,184 mg of carbon monoxide in a room.

10 ft = 3,048 m.

V (room) = 3,048 m · 3,048 m · 3,048 m.

V (room) = 28,33 m³.

d (carbon monoxide) = 6,5 mg/1000 m³ = 0,0065 mg/m³.

m (CO) = d (CO) · V (room)

m (CO) = 0,0065 mg/m³ · 28,33 m³.

m (CO) = 0,184 mg.