When 11.12 g of neon is combined in a 100 L container at 80oC with 9.59 g of argon, what is the mole fraction of argon?

The correct answer for the question that is being presented above is this one: " 0.3."

Here it is how to solve.

M olecular mass of Ar = 40

Molecular mass of Ne = 20

Number of moles of Ar = 9.59/40 = 0.239

Number of moles of Ne = 11.12/20 = 0.556

Mole fraction of argon = 0.239 / (0.239 + 0.556) = 0.3