How many moles of zinc are needed to react with 45.60 moles of nitric acid?

Question

Deanna Holland

Chemistry

24 October, 02:50

How many moles of zinc are needed to react with 45.60 moles of nitric acid?

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Answers (1)

Know the Answer?

Arnie · Answer 1

11.4 moles

Explanation:

Your chemical equation for the reaction of zinc and nitric acid will be

Zn + 4 HNO₃ - -> Zn (NO₃) ₂ + 2 NO₂ + 2 H₂O

To solve the problem, you need to use stoichiometry. For every 1 mole of zinc, you will need 4 moles of nitric acid. Divide 45.60 by 4. Your answer should be 11.4 moles.