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16 July, 22:53

Dry ice (solid CO2) has occasionally been used as an "explosive" in mining. A hole is drilled, dry ice and a small amount of gunpowder are placed in the hole, a fuse is added, and the hole is plugged. When lit, the exploding gunpowder rapidly vaporizes the dry ice, building up an immense pressure. Assume that 391 g of dry ice is placed in a cavity with a volume of 0.770 L and the ignited gunpowder heats the CO2 to 695 ∘C. What is the final pressure inside the hole?

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  1. 16 July, 22:59
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    Final pressure = 0.77atm

    Explanation:

    The concept used to approach this question is the Ideal gas equation

    PV = nRT

    where P = pressure

    V = Volume

    n = number of mole or amount of substance

    R = ideal gas constant

    T = Temperature in Kelvin

    from the parameters given; mass = 391g volume = 0.770 L Temperature = 695 ∘C = 695 + 273 = 968K R = 0.0821 number of moles = mass/molar mass molar mass of CO2 = 12 + 2x16 = 44g/mol number of moles = 391g/44g/mol = 8.886mol

    plugging into the equation to get the final pressure,

    from PV = nRT P = nRT/V = 8.886 x 0.0821 x 968 / 0.770 Final pressure = 0.77atm
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