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4 February, 13:07

Calculate the ph of a 0.10 m solution of hypochlorous acid, hocl. ka of hocl is 3.5*10-8 at 25 ∘c. express your answer numerically using two decimal places.

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  1. 4 February, 13:26
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    4.23.

    Explanation:

    ∵ pH = - log[H⁺].

    For weak acids:

    ∵ [H⁺] = √ (ka) (c).

    ∴ [H⁺] = √ (3.5 * 10⁻⁸) (0.10 M) = 5.92 x 10⁻⁵.

    ∴ pH = - log[H⁺] = - log (5.92 x 10⁻⁵) = 4.2279 ≅ 4.23.
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