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21 October, 00:57

How many grams of Cl are in a 38.0-g sample of CFCl3

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  1. 21 October, 00:59
    0
    Answer: 29.4 g Cl in CFCl3

    Explanation: (38.0 g CFCl3) / (137.3681 g CFCl3/mol) x (3 mol Cl / 1 mol CFCl3) x (35.4532 g Cl/mol) =

    29.4 g Cl in CFCl3
  2. 21 October, 01:19
    0
    38.0 g CF2Cl2) / (120.9135 g CF2Cl2/mol) x (2 mol Cl / 1 mol CF2Cl2) x (35.4532 g Cl/mol) =

    22.3 g Cl in CF2Cl2

    (38.0 g CFCl3) / (137.3681 g CFCl3/mol) x (3 mol Cl / 1 mol CFCl3) x (35.4532 g Cl/mol) =

    29.4 g Cl in CFCl3

    (38.0 g C2F3Cl3) / (187.3756 g C2F3Cl3/mol) x (3 mol Cl / 1 mol C2F3Cl3) x (35.4532 g Cl/mol) =

    21.6 g Cl in C2F3Cl3

    (38.0 g CF3Cl) / (104.4589 g CF3Cl/mol) x (1 mol Cl / 1 mol CF3Cl) x (35.4532 g Cl/mol) =

    12.9 g Cl in CF3Cl
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