A reaction is expected to produce 28.3 moles of hydrogen gas. If the hydrogen is collected at 297 K and 1.08 atm, what is the volume?

Volume = nRT/P

n = number of particles (moles)

R = universal gas constant (0.0821)

T = temperature of gas (Kelvin)

P = pressure (atm)

The equation can be set up as (28.3moles) (297K) (0.0821) / 1.08atm, which equals 639 L of hydrogen gas.

The answer is b. 639 L H2