Determine the rate of a reaction that follows the rate law rate = k a m b i where

Question

Paco

Chemistry

7 February, 13:22

Determine the rate of a reaction that follows the rate law rate = k a m b i where

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Answers (1)

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Maddox Cochran · Answer 1

(missing part of your question):

when we have K = 1 x 10^-2 and [A] = 2 M & [B] = 3M & m = 2 & i = 1

So when the rate = K[A]^m [B]^i

and when we have m + i = 3 so the order of this reaction is 3 So the unit of K is L^2. mol^-2S^-1

So by substitution:

∴ the rate = (1x 10 ^-2 L^-2. mol^-2S^-1) * (2 mol. L^-1) ^2 * (3mol. L^-1)

= 0.12 mol. L^-1. S^-1