How many grams of cl are in 445 g of cacl2?

284 g First, lookup the atomic weights of all the elements involved. Atomic weight of Calcium = 40.078 Atomic weight of Chlorine = 35.453 Now calculate the molar mass of CaCl2 40.078 + 2 * 35.453 = 110.984 Using that molar mass, calculate how many moles of CaCl2 you have. 445 g / 110.984 g/mol = 4.009586967 mol Since each molecule of CaCl2 has 2 chlorine atoms, multiply the number of moles of CaCl2 by 2 to get the number of moles of Chlorine atoms. 4.009586967 * 2 = 8.019173935 And finally, multiply by the atomic weight of chlorine. 8.019173935 * 35.453 = 284.3037735 Since you have have 3 significant figures in your data, round the result to 3 significant figures, giving 284 grams.