Mercury can be obtained by reacting mercury (II) sulfide with calcium oxide. How many grams of calcium oxide are needed to produce 36.0 g of Hg? 4HgS (s) + 4CaO (s) ® 4Hg (l) + 3CaS (s) + CaSO4

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Adam Robinson

Chemistry

27 August, 09:45

Mercury can be obtained by reacting mercury (II) sulfide with calcium oxide. How many grams of calcium oxide are needed to produce 36.0 g of Hg? 4HgS (s) + 4CaO (s) ® 4Hg (l) + 3CaS (s) + CaSO4

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Ayana Ochoa · Answer 1

Answer is: 10,024 grams of calcium oxide are needed.

m (Hg) = 36 g.

n (Hg) = m (Hg) : M (Hg).

n (Hg) = 36 g : 200,6 g/mol.

n (Hg) = 0,179 mol.

From chemical reaction: n (Hg) : n (CaO) = 4 : 4 (1 : 1).

n (CaO) = 0,179 mol.

n (CaO) = 0,179 mol · 56 g/mol.

n (CaO) = 10,024 g.