Use the equation. How much SiCl4 is needed to produce 2.7 moles HCl?

SiCl4 + 4 H2O - - > H4SiO4 + 4 HCl

4 moles of HCl are produced by 1 mole of SiCl4

2.7 moles of HCl will be produced if we have

2.7/4=0.675moles of SiCl4

molecular weight of SiCl4 = 169.9g

amount of SiCl4 needed = 169.9 X 0.675=114.682g

114.682 g is the answer