Ask Question
6 October, 23:14

An aluminum can holds 350 mL of gas at 0 C and 1.0 atm. what is the new volume if the can is heated to 10 C and the pressure inside the can rises to 75 atm?

+1
Answers (2)
  1. 6 October, 23:23
    0
    4.84mL

    Explanation:

    Step 1:

    Data obtained from the question. This include the following:

    Initial volume (V1) = 350mL

    Initial temperature (T1) = 0°C

    Initial pressure (P1) = 1atm

    Final temperature (T2) = 10°C

    Final pressure (P2) = 75atm

    Final volume (V2) = ... ?

    Step 2:

    Conversion of celsius temperature to Kelvin temperature.

    This can be achieved by using the formula below:

    T (K) = T (°C) + 273

    Initial temperature (T1) = 0°C

    Initial temperature (T1) = 0°C + 273 = 273K

    Final temperature (T2) = 10°C

    Final temperature (T2) = 10°C + 273 = 283K

    Step 3:

    Determination of the new volume.

    The new volume can be obtained by using the general gas equation as follow:

    P1V1/T1 = P2V2/T2

    1 x 350/273 = 75 x V2/283

    Cross multiply

    273 x 75 x V2 = 1 x 350 x 283

    Divide both side by 273 x 75

    V2 = (1 x 350 x 283) / (273 x 75)

    V2 = 4.84mL

    Therefore, the new volume is 4.84mL
  2. 6 October, 23:30
    0
    Final volume of the gas is 4.837mL

    Explanation:

    Initial volume (V1) = 350mL = 0.35L

    Initial temperature (T1) = 0°C = (0 + 273.15) k = 273.15k

    Initial pressure (P1) = 1.0atm

    Final volume (V2) = ?

    Final temperature (T2) = 10°C = (10 + 273.15) k = 283.15K

    Final pressure (P2) = 75atm

    To solve this question, we'll have to use combined gas equation which is the combination of all gas law I. e Charle's laws, Boyle's law, Pressure law etc.

    According to combined gas equation,

    (P1 * V1) / T1 = (P2 * V2) / T2

    Make V2 the subject of formula,

    V2 = (P1 * V1 * T2) / (P2 * T1)

    V2 = (1.0 * 0.35 * 283.15) / (75 * 273.15)

    V2 = 99.1025 / 20,486.25

    V2 = 0.004837L

    V2 = 4.837mL

    The final volume of the gas is 4.837mL
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An aluminum can holds 350 mL of gas at 0 C and 1.0 atm. what is the new volume if the can is heated to 10 C and the pressure inside the can ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers