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10 July, 03:53

1. Given the specific heat of lead is 0.129 J/g. C and that it takes 93.4J of energy to

heat a sample of lead from 22.3°C to 40.4°C find the mass of the lead.

m=

+2
Answers (1)
  1. 10 July, 04:01
    0
    Answer: 40 grams

    Explanation:

    The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

    Thus, Q = MCΦ

    Since Q = 93.4J

    M = ?

    C = 0.129 J/g. C

    Φ = 40.4°C - 22.3°C = 18.1°C

    Then, Q = MCΦ

    Make Mass, M the subject formula

    M = Q/CΦ

    M = (93.4J) / (0.129 J/g. C x 18.1°C)

    M = 93.4J / 2.33J/g

    M = 40 g

    Thus, the mass of the lead is 40 grams
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