Ask Question
1 May, 12:11

Calculate the percent yield when 500 grams of carbon dioxide react with an excess of water to produce 640 grams of carbonic acid.

CO2 + H2O - --> H2CO3

+4
Answers (1)
  1. 1 May, 12:31
    0
    Percent yield = 90.5%

    Explanation:

    Given dа ta:

    Mass of carbon dioxide = 500 g

    Mass of water = excess

    Actual yield of carbonic acid = 640 g

    Percent yield = ?

    Solution:

    Balanced chemical equation:

    CO₂ + H₂O → H₂CO₃

    Number of moles of carbon dioxide

    Number of moles = Mass / molar mass

    Number of moles = 500 g / 44 g/mol

    Number of moles = 11.4 mol

    Now we will compare the moles of H₂CO₃ with CO₂.

    CO₂ : H₂CO₃

    1 : 1

    11.4 : 11.4

    Mass of carbonic acid:

    Mass = number of moles * molar mass

    Mass = 11.4 mol * 62.03 g/mol

    Mass = 707.14 g

    Percent yield:

    Percent yield = actual yield / theoretical yield * 100

    Percent yield = 640 g / 707.14 g * 100

    Percent yield = 90.5%
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Calculate the percent yield when 500 grams of carbon dioxide react with an excess of water to produce 640 grams of carbonic acid. CO2 + H2O ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers