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3 February, 18:38

How many milliliters of ammonium sulfate solution having a concentration of 0.218 M are needed to react completely with 62.6 ml of 2.31 M sodium hydroxide solution?

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  1. 3 February, 18:39
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    330 mL of (NH₄) ₂SO₄ are needed

    Explanation:

    First of all, we determine the reaction:

    (NH₄) ₂SO₄ + 2NaOH → 2NH₃ + 2H₂O + Na₂SO₄

    We determine the moles of base:

    (First, we convert the volume from mL to L) → 62.6 mL. 1L/1000 mL = 0.0626L

    Molarity. volume (L) = 2.31 mol/L. 0.0626 L = 0.144 moles

    Ratio is 2:1. Therefore we make a rule of three:

    2 moles of hydroxide react with 1 mol of sulfate

    Then, 0.144 moles of NaOH must react with (0.144.1) / 2 = 0.072 moles

    If we want to determine the volume → Moles / Molarity

    0.072 mol / 0.218 mol/L = 0.330 L

    We convert from L to mL → 0.330L. 1000 mL/1L = 330 mL
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