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29 January, 04:45

What is the molarity of a solution prepared by dissolving 27.2 g of sodium chloride in enough water to prepare 500.0 ml of solution?

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  1. 29 January, 04:58
    0
    Molar mass NaCl : 58.44 g/mol

    number of moles:

    n = mass solute / molar mass

    n = 27.2 / 58.44

    n = 0.465 moles

    Volume in liters : 500.0 mL / 1000 = 0.5 L

    therefore:

    Molarity = moles solute / volume

    Molarity = 0.465 / 0.5 = > 0.93 M
  2. 29 January, 04:59
    0
    Molarity is calculated by dividing the number of moles of solute by the volume (in liters) of the solution.

    Moles NaCl, n: n = mass / molar mass = 27.2 g / (58.45 g/mol)

    n = 0.465 moles

    Molarity of solution:

    M = n / V = (0.465 moles) / (0.50 L) = 0.93 M

    Thus, the molarity of the solution is approximately 0.93 M.
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