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21 November, 22:46

36 g of water vapor takes up how many liters at room temperature and pressure of 293K and 100 K PA

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  1. 21 November, 23:12
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    Answer:-

    48.72 L

    Explanation:-

    We need to use the relation PV = nRT

    We are given Pressure P = 100 KPa.

    We are given Temperature T = 293 K

    We know Universal Gas constant R = 8.314 L KPa K-1 mol-1

    Mass of water = 36 gram

    Chemical formula of water = H2O

    Molecular weight of water = 1 x 2 + 16 x 1 = 18 g / mol

    Number of moles of water = 36 gram / (18 g / mol)

    = 2 mol

    Plugging in the values we get

    100 KPa x V = 2 mol x 8.314 L KPa K-1 mol-1 x 293 K

    V = (2 mol x 8.314 L KPa K-1 mol-1 x 293 K) / (100 KPa)

    = 48.72 L
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