The volume of a gas at 27.0c and 0.200atm is 80.0 ml. what volume will the same gas sample occupy at STP?

V₂ = 14.56 mL.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n is constant, and have different values of P, V and T:

(P₁*V₁) / T₁ = (P₂ * V₂) / T₂

Knowing that:

V₁ = 80.0 mL, P₁ = 0.20 atm, T₁ = 27 °C + 273 = 300 K.

V₂ = ? mL, P₂ (STP) = 1.0 atm, T₂ (STP) = 0 °C + 273 = 273 K.

Applying in the above equation

(P ₁ * V₁) / T₁ = (P₂ * V₂) / T₂

(0.20 atm * 80.0 mL) / 300 K = (1.0 atm * V₂) / 273 K

V₂ = (0.20 atm * 80.0 mL * 273 K) / (300 K * 1.0 atm)

V₂ = 14.56 mL

So, the answer is: V₂ = 14.56 mL.