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3 November, 02:13

What mass of hbr (in g) would you need to dissolve a 3.4 - g pure iron bar on a padlock?

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  1. 3 November, 02:24
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    Given:

    Mass of pure iron (Fe) = 3.4 g

    To determine:

    Mass of HBr needed to dissolve the above iron

    Explanation:

    Reaction between HBr and Fe is

    Fe + 2HBr → FeBr₂ + H₂

    Based on the reaction stoichiometry-

    1 mole of Fe reacts with 2 moles of HBr

    # moles of Fe = mass of Fe/atomic mass of Fe = 3.4/56 g. mol⁻¹ = 0.0607 moles

    Therefore # moles of HBr = 2*0.0607 = 0.1214 moles

    Molar mass of HBr = 81 g/mole

    Mass of HBr = 0.1214 moles * 81 g/mole = 9.83 g

    Ans: Mass of HBR required is 9.83 g
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