Calculate the mass of nickel metal which will react with 25mL of 0.15mol/L (

hydrochloric acid to produce nickel (II) chloride. 0.110625g

0.110625 g of Ni

Explanation:

The first step in solving this problem is to put down the accurate chemical reaction equation.

Ni (s) + 2HCl (aq) - --> NiCl2 (aq) + H2 (g)

Secondly, we obtain the amount of HCl that reacted from the information provided.

Volume of HCl (V) = 25 ml

Concentration of HCl (C) = 0.15 mol/L

Then, to find the number of moles of HCl (n);

n = CV

Substitution values

n = 25/1000 * 0.15

n = 3.75 * 10^-3 moles

Mass of 3.75 * 10^-3 moles of HCl = number of moles * molar mass

Molar mass of HCl = 36.5 gmol-1

Therefore;

Mass of HCl = 3.75 * 10^-3 moles * 36.5 gmol-1

Mass of HCl = 0.136875 g of HCl

Thirdly we determine the mass of Ni reacted;

If 1 mole of Ni reacted with 2 moles of HCl according to the reaction equation

Then x moles of Ni reacts with 3.75 * 10^-3 moles of HCl

x = 1 * 3.75 * 10^-3 moles / 2

x = 1.875 * 10^-3 moles of Ni

Mass of Ni = 1.875 * 10^-3 moles of Ni * 59 gmol-1

Mass of Ni = 0.110625 g of Ni