Ask Question
14 June, 03:14

Using the ideal gas equation, calculate the pressure of oxygen gas in a cylinder with a volume of 25.00 L. The oxygen masses 4.362 kg and room temperature is at 22.5 o C. How many moles of oxygen are there and what is the pressure of oxygen in atmospheres in the cylinder according to the ideal gas law?

+3
Answers (1)
  1. 14 June, 03:42
    0
    Equation: PV=nRT

    Rearrange: P=nRT/V

    Mols of oxygen = m/M = 4362g/16g/mol

    =272.625

    P=272.625*8.314 * (22.5+273.15) / 25

    =26804 pascales

    =0.26453491Atmosphere
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Using the ideal gas equation, calculate the pressure of oxygen gas in a cylinder with a volume of 25.00 L. The oxygen masses 4.362 kg and ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers