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23 June, 17:03

If a sample of oxygen gas originally at from 171.4 K has its temperature increased to 288.4 K and

the new volume was 1.6 L, what was the original volume of the sample of oxygen gas?

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  1. 23 June, 17:24
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    V₂ = 0.95 L

    Explanation:

    Given dа ta:

    Initial temperature of gas = 171.4 K

    Final temperature of gas = 288.4 K

    Final volume = 1.6 L

    Initial volume = ?

    Solution:

    The given problem will be solve through the Charles Law.

    According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

    Mathematical expression:

    V₁/T₁ = V₂/T₂

    V₁ = Initial volume

    T₁ = Initial temperature

    V₂ = Final volume

    T₂ = Final temperature

    Now we will put the values in formula.

    V₁/T₁ = V₂/T₂

    V₁ = V₂T₁ / T₂

    V₂ = 1.6 L * 171.4 K / 288.4 k

    V₂ = 274.24 L. K / 288.4 K

    V₂ = 0.95 L
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