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13 January, 14:51

In the following reaction: 4 Al + 3 O2 - > 2 Al2O3 How many moles of aluminum would be needed to completely react with 90 grams of O2?

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  1. 13 January, 15:09
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    molar ratio = 4:3

    since al moles needed so we will leave al in moles and convert o into grams

    4: since 1 mole of oxygen is 16g so 3 moles is 48

    4:48

    put given data

    x:90

    90*4/48

    7.5 moles
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